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Question 643043: Can you please hep me solve this problem. Its part of my summer math packet and i can't figure it out. the problem is : Sean collects nickels and dimes. Every time he places a nickel into his collection, he places two dimes. After a week, he notices that the number of dimes, increased by twice the number of nickels, gives the same number of coins as three times the number of nickels, increased by 10. How many coins does he have by the end of the week?
Ive tried over and over again but i keep getting confused thank you for your help.
Jasdeep Kaur
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Sean collects nickels and dimes. Every time he places a nickel into his collection, he places two dimes.
d = 2n
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After a week, he notices that the number of dimes, increased by twice the number of nickels, gives the same number of coins as three times the number of nickels, increased by 10.
d + 2n = 3n + 10
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How many coins does he have by the end of the week?
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Substitute for "d" and solve for n:
2n + 2n = 3n + 10
n = 10 (# of nickels)
Solve for "d":
d = 2n = 20 (# of dimes)
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Total number of coins: 10 + 20 = 30
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Cheers,
Stan H.
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