SOLUTION: We have a one pound coffee can. We will fill that can about 80% full with a grain that contains 12% protein. We will then fill the remaining 20% with another grain that contains

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Question 642967: We have a one pound coffee can. We will fill that can about 80% full with a grain that contains 12% protein. We will then fill the remaining 20% with another grain that contains 32% protein. What is the total percentage of protein the horse will receive a feeding? How much of each grain (the 12% protein and the 32% protein) should we put into that one pound coffee can so that the horse receives a total of only 15% protein?
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
We have a one pound coffee can.
We will fill that can about 80% full with a grain that contains 12% protein.
We will then fill the remaining 20% with another grain that contains 32% protein.
What is the total percentage of protein the horse will receive a feeding?
How much of each grain (the 12% protein and the 32% protein) should we put
into that one pound coffee can so that the horse receives a total of only
15% protein?
:
Let deal with this in ounces, 16 oz in 1 pound
.8(16) = 12.8 oz of 12% protein
.2(16) = 3.2 oz of 32% protein
:
"What is the total percentage of protein the horse will receive a feeding? "
.12(12.8) + .32(3.2) = 16x
1.536 + 1.024 = 16x
2.56 = 16x
x = 2.56/16
x = .16 * 100 = 16% protein in this mixture
:
" How much of each grain (the 12% protein and the 32% protein) should we
put into that one pound coffee can so that the horse receives a total of
only 15% protein?
:
Let a = amt of 32% grain required to accomplish this
then
(16-a) = amt of 12% grain
:
.12(16-a) + .32a = .15(16)
1.92 - .12a + .32a = 2.4
.20a = 2.4 - 1.92
.2a = .48
a = .48/.2
a = 2.4 oz of 32% grain
then
16-2.4 = 13.6 oz of 12% grain