SOLUTION: We have 24 Gallons of 10% lemonade. how many gallons of pure water must be added to produce 6% lemonade?
so far i have: 21.6 gal of water in the 10% solution
x gal of pure wat
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so far i have: 21.6 gal of water in the 10% solution
x gal of pure wat
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Question 642948: We have 24 Gallons of 10% lemonade. how many gallons of pure water must be added to produce 6% lemonade?
so far i have: 21.6 gal of water in the 10% solution
x gal of pure water
.94(24+x)gal of 6% lemonade
then i set up this equation: 21.6+x=.94(24+x)
after solving i got 16 gal of pure water. Is this correct?
You can put this solution on YOUR website! We have 24 Gallons of 10% lemonade.
how many gallons of pure water must be added to produce 6% lemonade?
:
You are right but took the hard way to do it, a simple equation would be
.10(24) = .06(x+24)
2.4 = .06x + 1.44
2.4- 1.44 = .06x
.96 = .06x
x = .96/.06
x = 16 gal
