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| Question 6428:  I need help with these problems can you solve these out for me in steps?
 Set 5
 1. factor completely: x to the 2nd power -7x -30
 2. factor completely: x to the 2nd power + 4x -16
 3. factor completely: 2x to the 2nd power -11x+5
 4. factor completely: 4x to the 2nd power +20x-24
 5. factor completely: 4m to the 2nd power - 9
 6. factor completely: 16a to the 2nd power - 25b to the 2nd power
 7. solve by factoring: x to the 2nd power -x-12=0
 8. solve by factoring: 2c to the 2nd power -5=-9c
 9. solve the equation:(x+6)(x-7)(x-8)(x+9)=0
 10. find the dimensions of the rectangle if the width is 3 feet less than the length and the area is  40ft to the 2nd power
 Answer by ichudov(507)
      (Show Source): 
You can put this solution on YOUR website! I'll do a couple for you.... 
 
 | Solved by pluggable solver: EXPLAIN simplification of an expression |  | Your Result: 
 
 
 
  YOUR ANSWER
 | 
This is an equation! Solutions: x=-6,x=7,x=8,x=-9.
Graphical form: Equation  was fully solved.Text form: (x+6)*(x-7)*(x-8)*(x+9)=0 simplifies to 0=0Cartoon (animation) form:   For tutors:
 simplify_cartoon( (x+6)*(x-7)*(x-8)*(x+9)=0 )If you have a website, here's a link to this solution.  | 
 DETAILED EXPLANATIONLook at
  . Notes known roots (x-(-6))
 
 Look at
  . Remove unneeded parentheses around factor
  It becomes
  . 
 Look at
  . Remove extraneous '1' from product
  It becomes
  . 
 Look at
  . Notes known roots (x-(7))
 
 Look at
  . Remove unneeded parentheses around factor
  It becomes
  . 
 Look at
  . Remove extraneous '1' from product
  It becomes
  . 
 Look at
  . Notes known roots (x-(8))
 
 Look at
  . Remove unneeded parentheses around factor
  It becomes
  . 
 Look at
  . Remove extraneous '1' from product
  It becomes
  . 
 Look at
  . Remove unneeded parentheses around terms
  ,  It becomes
  . 
 Look at
  . Solved linear equation
  equivalent to  x+9  =0 It becomes
  . Result:
  This is an equation! Solutions: x=-6,x=7,x=8,x=-9.
 
 
 Universal Simplifier and SolverDone!
 
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 | Solved by pluggable solver: SOLVE quadratic equation with variable |  | Quadratic equation  (in our case  ) has the following solutons: 
 
  
 For these solutions to exist, the discriminant
  should not be a negative number. 
 First, we need to compute the discriminant
  :  . 
 Discriminant d=81 is greater than zero. That means that there are two solutions:
  . 
 
  
  
 Quadratic expression
  can be factored: 
  Again, the answer is: 5, 0.5.
Here's your graph:
 
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