SOLUTION: y=(x+5)^2 Give the coordinates of the x intercepts (if they exits) for the graph of each equation. in simplest form thanks so much for your help in advance!

Algebra ->  Graphs -> SOLUTION: y=(x+5)^2 Give the coordinates of the x intercepts (if they exits) for the graph of each equation. in simplest form thanks so much for your help in advance!      Log On


   

Question 642797: y=(x+5)^2
Give the coordinates of the x intercepts (if they exits) for the graph of each equation. in simplest form thanks so much for your help in advance!
Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
Answer: (-5,0)
Solution:
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B10x%2B25+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%2810%29%5E2-4%2A1%2A25=0.

Discriminant d=0 is zero! That means that there is only one solution: x+=+%28-%2810%29%29%2F2%5C1.
Expression can be factored: 1x%5E2%2B10x%2B25+=+1%28x--5%29%2A%28x--5%29

Again, the answer is: -5, -5. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B10%2Ax%2B25+%29