SOLUTION: solve for x over the interval -2pi,2pi: 2sin(x+(pi/4))=1. Can you also show how you got the answer

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Question 642735: solve for x over the interval -2pi,2pi: 2sin(x+(pi/4))=1. Can you also show how you got the answer
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve for x over the interval -2pi,2pi: 2sin(x+(pi/4))=1
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-2pi,2pi is not a correct expression for an interval
I will assume an interval of [0,2π)
2sin(x+π/4))=1
sin(x+π/4))=1/2
x+π/4=π/6 and 5π/6 (in quadrants I and II where sin>0)
x=π/6-π/4=2π/12-3π/12=-π/12
or
x=5π/6-π/4=10π/12-3π/12=7π/12