SOLUTION: I am not good with factoring the polynomials and I need help. What are the steps for factoring a polynomial? Could you tell me the steps and give me some examples to go off of? Tha

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I am not good with factoring the polynomials and I need help. What are the steps for factoring a polynomial? Could you tell me the steps and give me some examples to go off of? Tha      Log On


   



Question 642353: I am not good with factoring the polynomials and I need help. What are the steps for factoring a polynomial? Could you tell me the steps and give me some examples to go off of? Thanks.
Found 2 solutions by jim_thompson5910, solver91311:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Here's an example

Factor: 3x%5E2%2B+49x+%2B+16



Looking at the expression 3x%5E2%2B49x%2B16, we can see that the first coefficient is 3, the second coefficient is 49, and the last term is 16.


Now multiply the first coefficient 3 by the last term 16 to get %283%29%2816%29=48.


Now the question is: what two whole numbers multiply to 48 (the previous product) and add to the second coefficient 49?


To find these two numbers, we need to list all of the factors of 48 (the previous product).


Factors of 48:
1,2,3,4,6,8,12,16,24,48
-1,-2,-3,-4,-6,-8,-12,-16,-24,-48


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 48.
1*48 = 48
2*24 = 48
3*16 = 48
4*12 = 48
6*8 = 48
(-1)*(-48) = 48
(-2)*(-24) = 48
(-3)*(-16) = 48
(-4)*(-12) = 48
(-6)*(-8) = 48

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 49:


First NumberSecond NumberSum
1481+48=49
2242+24=26
3163+16=19
4124+12=16
686+8=14
-1-48-1+(-48)=-49
-2-24-2+(-24)=-26
-3-16-3+(-16)=-19
-4-12-4+(-12)=-16
-6-8-6+(-8)=-14



From the table, we can see that the two numbers 1 and 48 add to 49 (the middle coefficient).


So the two numbers 1 and 48 both multiply to 48 and add to 49


Now replace the middle term 49x with x%2B48x. Remember, 1 and 48 add to 49. So this shows us that x%2B48x=49x.


3x%5E2%2Bhighlight%28x%2B48x%29%2B16 Replace the second term 49x with x%2B48x.


%283x%5E2%2Bx%29%2B%2848x%2B16%29 Group the terms into two pairs.


x%283x%2B1%29%2B%2848x%2B16%29 Factor out the GCF x from the first group.


x%283x%2B1%29%2B16%283x%2B1%29 Factor out 16 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x%2B16%29%283x%2B1%29 Combine like terms. Or factor out the common term 3x%2B1


===============================================================


Answer:


So 3x%5E2%2B49x%2B16 factors to %28x%2B16%29%283x%2B1%29.


In other words, 3x%5E2%2B49x%2B16=%28x%2B16%29%283x%2B1%29.


Note: you can check the answer by expanding %28x%2B16%29%283x%2B1%29 to get 3x%5E2%2B49x%2B16 or by graphing the original expression and the answer (the two graphs should be identical).

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Factoring polynomials is something like 3 or 4 weeks of a course of instruction in Algebra 1. Do you seriously expect someone to put that much information in to one of these little answer boxes?

Go back and read the instructions for posting, especially the one that says to be specific about the ONE problem you submit per post and to show the work you have done so far.

John

My calculator said it, I believe it, that settles it
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