Question 641859: Train 1 leaves city A at 10:00 a.m. heading towards city B, 300 miles to the east, at 45 miles per hour. At 11:00 a.m., train 2 leaves city A from city B at 55 miles per hour. Which train will complete the trip first and when will it pass the other?
I got this so far:
R*T = D
(45)*(1) = 45 mi head start for train 1
(45)*T = (300 - 45)
T = 5.7 hrs for train 1
(55)*T = 300
T = 5.45 hrs for train 2
so train 2 completes the trip first but I don't know when it will pass train 1. Please help me!!!
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Train 1 leaves city A at 10:00 a.m. heading towards city B, 300 miles to the
east, at 45 miles per hour.
At 11:00 a.m., train 2 leaves city A from city B at 55 miles per hour.
Which train will complete the trip first and when will it pass the other
:
Let t = travel time of Train 2; (started at 11 AM)
then
(t+1) = travel time of Train 1 (left one hr earlier)
:
You are right about which train will arrive first
:
"when will they pass each other"
When they meet, the sum of the distances traveled will = 300 mi
55t + 45(t+1) = 300
55t + 45t + 45 = 300
100t = 300-45
100t = 255
t = 255/100
t = 2.55 hrs which is 2 + .55(60) = 2:33, from 11 am; 1:33 PM they meet
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