SOLUTION: I did the first part of this problem and it took me 3 days. I am now stuck on this second part. Please can someone help me with this? An explanation of what the parts of the for

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I did the first part of this problem and it took me 3 days. I am now stuck on this second part. Please can someone help me with this? An explanation of what the parts of the for      Log On


   



Question 641622: I did the first part of this problem and it took me 3 days. I am now stuck on this second part. Please can someone help me with this?
An explanation of what the parts of the formula mean before using it to get your answers. A discussion of how and why these concepts are important in the “real world.” Describe another situation that could be evaluated using these concepts.
Sailboat stability. To be considered safe for ocean sailing, the capsize screening value C should be less than 2 (www.sailing.com). For a boat with a beam (or width) b in feet and displacement d in pounds, C is determined by the function C = 4d^-1/3b.
a) Find the capsize screening value for the Tartan 4100, which has a displacement of 23,245 pounds and a beam of 13.5 feet.
b) Solve this formula for d.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

I did the first part of this problem and it took me 3 days. I am now stuck on this second part. Please can someone help me with this?
An explanation of what the parts of the formula mean before using it to get your answers. A discussion of how and why these concepts are important in the “real world.” Describe another situation that could be evaluated using these concepts.
Sailboat stability. To be considered safe for ocean sailing, the capsize screening value C should be less than 2 (www.sailing.com). For a boat with a beam (or width) b in feet and displacement d in pounds, C is determined by the function C = 4d^-1/3b.
a) Find the capsize screening value for the Tartan 4100, which has a displacement of 23,245 pounds and a beam of 13.5 feet.
b) Solve this formula for d.

C+=+4d%5E-1%2F3b
For the 1st part, a, substituting 23,245 for d, and 13.5 feet for b, you should have gotten: highlight_green%28C+=+4.24889%5E-6%29

Part b
C+=+4d%5E-1%2F3b

C+=+4+%2A+%281%2Fd%5E1%29%2F3b

C+=+4+%2A+%281%2Fd%29%2F3b

C+=+%284%2Fd%29%2F3b

C+=+%284%2Fd%29+%2A+%281%2F3b%29

C+=+4%2F3bd

3bCd+=+4 ------- Cross-multiplying

highlight_green%28d+=+4%2F3bC%29

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