SOLUTION: one number is 3 times another. the sum of their reciprocals is 20/3. find the numbers

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Question 641184: one number is 3 times another. the sum of their reciprocals is 20/3. find the numbers
Answer by josh_jordan(263) About Me  (Show Source):
You can put this solution on YOUR website!
To solve, let's turn the sentences into equations. The first sentence says that one number is 3 times another. In other words:
x = 3y
The next sentence says that the sum of their reciprocals is 20/3. In other words:
1%2Fx+%2B+1%2Fy+=+20%2F3
To solve, we need to substitute x in the second equation, with 3y, that way we will get rid of x and solve for y:
1%2F3y+%2B+1%2Fy+=+20%2F3
Next, multiply the equation by 3y. This will get rid of our fractions and leave us with:
1+%2B+3+=+20y =
4+=+20y
Divide both sides of the equation by 20, and this will leave us with y, which will be one of our numbers:
y+=+4%2F20 = y+=+1%2F5
So, 1/5 is one of our numbers.
We know that the other number is 3 times y. So, 3 x 1/5 will give us our other number:
3 x 1/5 = 3/5
FINAL ANSWER: 1/5 and 3/5 are the numbers