SOLUTION: Hi! Could someone please help me with this problem. Let x=4,y=-3 and z=2 xy^2-3z^2 ----------- (xy)^2(-3z)^2

Algebra ->  Systems-of-equations -> SOLUTION: Hi! Could someone please help me with this problem. Let x=4,y=-3 and z=2 xy^2-3z^2 ----------- (xy)^2(-3z)^2      Log On


   



Question 64111: Hi! Could someone please help me with this problem.
Let x=4,y=-3 and z=2
xy^2-3z^2
-----------
(xy)^2(-3z)^2

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
xy^2-3z^2 ......=4*(-3)^2-3(2)^2=4*9-3*4=36-12=24
-----------.........---------------------------------------------------------
(xy)^2(-3z)^2...=(4*-3)^2(-3*2)^2=-12^2*-6^2=144*36=5184
24/5184=1/216