SOLUTION: Maria lights two candles of equal length at the same time. One candle takes 6 hours to burn out and the other takes 9 hours. How much time will pass until the slower burning candle

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Question 640870: Maria lights two candles of equal length at the same time. One candle takes 6 hours to burn out and the other takes 9 hours. How much time will pass until the slower burning candle is exactly twice as long as the faster burning one? Explain your answer.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Since the candles can be any length, I will say
they are both +18+ units long, and the units
can be anything I choose.
The fast burning candle burns at a rate of +18%2F6+=+3+ units/hr
The slow burning candle burns at a rate of +18%2F9+=+2+ units/hr
Let +x+ = the units that the fast burning candle
burns off in +t+ hrs
+18+-+x+ is the length that is left
It is given that +2%2A%28+18+-+x+%29+ is the length left of the slow burning candle
+18+-+2%2A%28+18+-+x+%29+ is the length of the slow burning candle
that has burned away
-----------------
Equation for fast-burning candle:
(1) +x+=+3t+
Equation for slow-burning candle:
(2) +18+-+2%2A%28+18+-+x+%29+=+2t+
------------------------
Substitute (1) into (2)
(2) +18+-+2%2A%28+18+-+3t+%29+=+2t+
(2) +18+-+36+%2B+6t+=+2t+
(2) +-18+=+-4t+
(2) +t+=+9%2F2+
In 4 and one half hours the slower burning
candle is twice as long as the faster burning candle
-------------
check:
(1) +x+=+3%2A%289%2F2%29+
(1) +x+=+27%2F2+
and
(2) +18+-+2%2A%28+18+-+27%2F2+%29+=+2t+
(2) +18+-+2%2A%28+36%2F2+-+27%2F2+%29+=+2t+
(2) +18+-+36+%2B+27+=+2t+
(2) +9+=+2t+
(2) +t+=+9%2F2+
OK