SOLUTION: Horriable at fractions any help would be greatly appreciated. It is a fraction with the exponet being the 2/3 and 1/3. (25x^3) 2/3 (125xy^2) 1/3

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Horriable at fractions any help would be greatly appreciated. It is a fraction with the exponet being the 2/3 and 1/3. (25x^3) 2/3 (125xy^2) 1/3      Log On


   

Question 64073: Horriable at fractions any help would be greatly appreciated. It is a fraction with the exponet being the 2/3 and 1/3.
(25x^3) 2/3
(125xy^2) 1/3
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(25x^3)^(2/3)
Multiply the 2/3 and the 3 to get:
=25^2
=625
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(125xy^2)^(1/3)
The 1/3 means "take the cube root"
=5x^(1/3)y^(2/3)
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Cheers,
Stan H.