SOLUTION: A man wishes to fence in a rectangular lot. If he uses materials costing 1.70 dollar a foot for the front of the lot and material costing 1.40 dollar a foot for the other three sid
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Question 640698: A man wishes to fence in a rectangular lot. If he uses materials costing 1.70 dollar a foot for the front of the lot and material costing 1.40 dollar a foot for the other three side the fence will cost 890 dollar. If he uses the cheaper material for all four side of the lot the fence will cost 854 dollar. Find t dimension of the lot. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A man wishes to fence in a rectangular lot.
If he uses materials costing 1.70 dollar a foot for the front of the lot and
material costing 1.40 dollar a foot for the other three side the fence will
cost 890 dollar.
If he uses the cheaper material for all four side of the lot the fence will
cost 854 dollar. Find t dimension of the lot.
:
Let L & W be the dimensions of the lot
1st scenario
1.70L + 1.40L + 1.40(2W) = 890
3.10L + 2.80W = 890
:
2nd scenario
1.40(2L) + 1.40(2W) = 854
2.80L + 2.80W = 854
Subtract the above equation from the 1st equation
3.10L + 2.80W = 890
2.80L + 2.80W = 854
--------------------subtraction eliminates W, find L
.30L = 36
L = 36/.3
L = 120 ft is the length
then
2.80L + 2.80W = 854
2.8(120) + 2.8W = 854
336 + 2.8W = 854
2.8W = 854 - 336
2.8W = 518
W = 518/2.8
W = 185 ft is the width
:
:
Check this out in the 1st equation
3.10(120) + 2.8(185) =
372 + 518 = 890
