Question 640393: suppose a chemist has 10% and 15% acid solutions in stock. how much of each should the chemist mix if 100ml of a 12% solution is desired? Found 2 solutions by sachi, Earlsdon:Answer by sachi(548) (Show Source):
You can put this solution on YOUR website! let x ml of 10% & 100-x ml of 15% acid soln were mixed to get 100 ml of 12% soln
so 10x/100+15[100-x]/100=12
or 10x+15[100-x]=1200
or -5x=1200-1500=-300
or x=60 ml of 10% & 40 ml of 15% soln were mixed
ans
You can put this solution on YOUR website! First express the problem in terms of the amount of acid in the acid solutions.
For example, in 10ml of a 10% acid solution, there are 10% of 10ml (0.1(10)) of acid which gives us 1ml of acid.
For this problem, if we lex x = the number of ml of 10% acid solution and (100-x) = the amount of 15% acid solution, we can express the amounts of acid thus:
0.1x+0.15(100-x) = 0.12(100) Simplify and solve for x.
0.1x+15-0.15x = 12
-0.05x+15 = 12 Subtract 15
-0.05x = -3 Divide by -0.05
x = 60ml
The chemist will need to mix 60ml of the 10% acid solution with (100-x = 40)ml of the 15% acid solution to obtain 100ml of 12% acid solution.
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