SOLUTION: y varies jointly with p and q. When p = 5 and q = 2, y = 80. Find y when p = 4 and q = 5.
PLEASE ANSWER, NEED HELP
Algebra ->
Expressions-with-variables
-> SOLUTION: y varies jointly with p and q. When p = 5 and q = 2, y = 80. Find y when p = 4 and q = 5.
PLEASE ANSWER, NEED HELP
Log On
Don't type in all caps. It is rude and annoying and makes you look ignorant. Apologies and lame excuses just make you look dumber. Don't say anything; just stop doing it.
If varies jointly with and , then
Substitute the initial values given for , , and and then solve for , the constant of proportionality. Once you have a value for you can use that with the second set of values given for and to solve for
John
My calculator said it, I believe it, that settles it