SOLUTION: y varies jointly with p and q. When p = 5 and q = 2, y = 80. Find y when p = 4 and q = 5. PLEASE ANSWER, NEED HELP

Algebra ->  Expressions-with-variables -> SOLUTION: y varies jointly with p and q. When p = 5 and q = 2, y = 80. Find y when p = 4 and q = 5. PLEASE ANSWER, NEED HELP      Log On


   



Question 640288: y varies jointly with p and q. When p = 5 and q = 2, y = 80. Find y when p = 4 and q = 5.
PLEASE ANSWER, NEED HELP

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Don't type in all caps. It is rude and annoying and makes you look ignorant. Apologies and lame excuses just make you look dumber. Don't say anything; just stop doing it.

If varies jointly with and , then



Substitute the initial values given for , , and and then solve for , the constant of proportionality. Once you have a value for you can use that with the second set of values given for and to solve for

John

My calculator said it, I believe it, that settles it
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