Question 640287: Mr. And mrs. Wolfe both make 12$ an hour at work. One week mrs. Wolfe worked four hours more than her husband. Their combined pay for the week was 912$. How many hours did each work?
Found 2 solutions by unlockmath, josh_jordan:
Answer by unlockmath(1688)   (Show Source):
You can put this solution on YOUR website! Hello,
Let's set up an equation as:
Let x represent the hours.
12x+12x+4(12)=912
Combine like terms and subtract 4:
24x=908
Divide by 24:
x=36 hours rewritten as:
36 for Mr Wolfe
40 hours for Mrs. Wolfe
Make sense?
RJ
www.math-unlock.com
Answer by josh_jordan(263)  (Show Source):
You can put this solution on YOUR website! To solve, we need to set this problem up as equations:
MR = $12
MRS = $12
The second sentence says Mrs Wolfe worked 4 more hours than her husband. In other words,
MRS = MR + 4
Their combined pay for the week was $912. So,
$12 x MR hours + $12(MR hours + 4) = $912 =
$12MR + $12MR + $48 = $912
Combining, we get
$24MR + $48 = $912
Subtract $48 from both sides of our equation, so that we can eventually get MR by himself:
$24MR + $48 - $48 = $912 - $48 =
$24MR = $864
Dividing both sides by $24 will get MR (MR's hours) by itself:
MR = 36
So, Mr Wolfe worked 36 hours
Mrs Wolfe worked 4 more hours than he did, so 36 + 4 = 40
So, Mrs Wolfe worked 40 hours
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