SOLUTION: If sin x = 1/3 and sec y = 3/4, where x and y lie between 0 and pi/2, evaluate sin(x+y)

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Question 640250: If sin x = 1/3 and sec y = 3/4, where x and y lie between 0 and pi/2, evaluate sin(x+y)
Answer by Alan3354(69443) About Me  (Show Source):
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If sin x = 1/3 and sec y = 3/4, where x and y lie between 0 and pi/2, evaluate sin(x+y)
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secant cannot be 3/4 (unless y is a complex number)