SOLUTION: A rectangle is three times as long as it is wide.If its length and width are both decreased by 2 cm,its area is decreased by 36 cm squared.Find its original dimensions.Make a sketc

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Question 64023This question is from textbook Algebra Structure and Method Book1
: A rectangle is three times as long as it is wide.If its length and width are both decreased by 2 cm,its area is decreased by 36 cm squared.Find its original dimensions.Make a sketch as in Oral Exercise 2. This question is from textbook Algebra Structure and Method Book1

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
The area of a rectangle is given by:
A+=+L%2AW
In your rectangle: L+=+3W
If you decrease the length, L, and the width, W, each by 2 cm, the area, A, is decreased by 36 sq.cm. So, puting this into an equation, you'll get:
%28L-2%29%28W-2%29+=+A-36 Substituting 3W for L, and L*W for A, you now have:
%283W-2%29%28W-2%29+=+3W%5E2-36 Simplifying this, you'll get:
3W%5E2-8W%2B4+=+3W%5E2+-+36 Further simplification yields:
-8W%2B4+=+-36 and:
-8W+=+-40 Dividing by -8:
W+=+5 and
L+=+3W so:
L+=+15
The original length, L = 15 cm
The original width, W = 5 cm
Check:
Original area:
A1+=+%2815%29%285%29
A1+=+75+cm%5E2
After decreasing the lenth and width by 2 cm:
A2+=+%2813%29%283%29
A2+=+39 sq.cm.
The decrease in area is:
75-39+=+36sq.cm.