SOLUTION: I am trying to simplify the equation for an ellipse so that it is in the standard form of "x^2/a^2+y^2/b^2=1". The equation is 9x^2+36y^2=4. I have tried to factor the 9 out of t

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I am trying to simplify the equation for an ellipse so that it is in the standard form of "x^2/a^2+y^2/b^2=1". The equation is 9x^2+36y^2=4. I have tried to factor the 9 out of t      Log On


   



Question 639804: I am trying to simplify the equation for an ellipse so that it is in the standard form of "x^2/a^2+y^2/b^2=1". The equation is 9x^2+36y^2=4. I have tried to factor the 9 out of the right side of the equation, and then dividing the entire equation by 4. Also, dividing by 4 without factoring had lead me to a dead end. What should I do to get the equation to the standard form?
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I am trying to simplify the equation for an ellipse so that it is in the standard form of "x^2/a^2+y^2/b^2=1". The equation is 9x^2+36y^2=4. I have tried to factor the 9 out of the right side of the equation, and then dividing the entire equation by 4. Also, dividing by 4 without factoring had lead me to a dead end. What should I do to get the equation to the standard form?
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standard form of equation for an ellipse with vertical major axis and center at (0,0): x%5E2%2Fb%5E2%2By%5E2%2Fa%5E2=1
9x%5E2%2B36y%5E2=4
divide by 4
x%5E2%2F%289%2F4%29%2By%5E2%2F%2836%2F4%29=1
x%5E2%2F%289%2F4%29%2By%5E2%2F9=1
x%5E2%2F2.25%2By%5E2%2F9=1
b^2=9/4=2.25
a^2=9
..
note:9x%5E2%2F4=x%5E2%2F%289%2F4%29=x%5E2%2F2.25
36y%5E2%2F4=y%5E2%2F%2836%2F4%29=y%5E2%2F9