SOLUTION: find perimeter of triangle whose vertices are (4,10), (9,-4),(8,1)

Algebra ->  Triangles -> SOLUTION: find perimeter of triangle whose vertices are (4,10), (9,-4),(8,1)      Log On


   

Question 639795: find perimeter of triangle whose vertices are (4,10), (9,-4),(8,1)
Answer by mananth(16949) About Me  (Show Source):
You can put this solution on YOUR website!
P(4,10), Q(9,-4),R(8,1)
Find the distance PQ, QR, RS
P(4,10), Q(9,-4)
x1 y1 x2 y2

4 10 9 -4
d= sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29
d= sqrt%28%28-4-10%09%29%5E2%2B%289-4%29%5E2%09%29
d= sqrt%28%28-14%29%5E2%09%2B%285%29%5E2%09%29
d= sqrt%28%28%09%09221%09%29++%09%29
d(P,Q)= 14.87
Q(9,-4),R(8,1)
x1 y1 x2 y2

9 -4 8 1
d= sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29
d= sqrt%28%281-%28-4%29%09%29%5E2%2B%288-9%29%5E2%29
d= sqrt%28%285%29%5E2%2B%28-1%29%5E2%09%29
d= sqrt%28%28%09%0926%09%29++%09%29
dQ,R)= 5.10
RR(8,1),P(4,10)
x1 y1 x2 y2

8 1 4 10
d= sqrt%28%28y2-y1%29%5E2%2B%28x2-x1%29%5E2%29
d= sqrt%28%2810-1%29%5E2%2B%284-8%29%5E2%29
d= sqrt%28%289%29%5E2%2B%28%09-4%29%5E2%09%29
d= sqrt%28%28%09%0997%09%29++%09%29
d= 9.85
Add up all the three distances