SOLUTION: A woman invests 4 times as much at 5% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $520. How much did she invest at each rate?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A woman invests 4 times as much at 5% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $520. How much did she invest at each rate?      Log On


   

Question 63962This question is from textbook Beginning Algebra
: A woman invests 4 times as much at 5% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $520. How much did she invest at each rate? This question is from textbook Beginning Algebra

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A woman invests 4 times as much at 5% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $520. How much did she invest at each rate?
:
Let x = the 6% amt invested
Then 4x = the 5% amt invested
:
.05(4x) + .06x = 520
.2x + .06x = 520
.26x = 520
x = 520/.26
x = $2000 invested at 6%
:
4(2000) = $8000 invested at 5%
:
:
Check:
.05(8000) + .06(2000) =
400 + 120 = 520