Question 639474: Two investments totaling $16,000 produce an annual income of $1140. One investment yields at 6% a year, while the other yields at 8% per year. How much is invested at each rate?
I have read this word problem over 20 times. Please help solve this word problem.
principal=16,000
interest=1140
rate
Answer by MathTherapy(10552)   (Show Source):
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Two investments totaling $16,000 produce an annual income of $1140. One investment yields at 6% a year, while the other yields at 8% per year. How much is invested at each rate?
I have read this word problem over 20 times. Please help solve this word problem.
principal=16,000
interest=1140
rate
Let amount invested at 6% be S
Then amount invested at 8% = 16,000 - S
Interest earned at 6%, plus interest earned at 8%, equals total interest earned
We therefore have: .06(S) + .08(16,000 - S) = 1,140
.06S + 1,280 - .08S = 1,140
.06S - .08S = 1,140 - 1,280
- .02S = - 140
S, or amount invested at 6% =  , or $
Amount invested at 8% = $16,000 - 7,000, or $
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