SOLUTION: I don't even know where to begin with this, please help explain the steps.
Solve: 2*log4(x)+3*log8(x)=10
Thank You
Algebra ->
Functions
-> SOLUTION: I don't even know where to begin with this, please help explain the steps.
Solve: 2*log4(x)+3*log8(x)=10
Thank You
Log On
Question 639398: I don't even know where to begin with this, please help explain the steps.
Solve: 2*log4(x)+3*log8(x)=10
Thank You Answer by opeodu(24) (Show Source):
You can put this solution on YOUR website! 2Log4x+3log8x=10 log4x^2+log8x^3=10 using law of logarithm that log(baseN^b)a=1/blog(baseN)a 1/2log2x^2+1/3log2x^3 log2x+log2x=10 log2x^2=10 x^2=2^10 x=2^5=32
