SOLUTION: I need to solve the following for x where degrees 0 <x < 2pi for the a) 3sinx=2cos(2x-1) b) sin(cosx)=3cos(x-2)

Algebra ->  Trigonometry-basics -> SOLUTION: I need to solve the following for x where degrees 0 <x < 2pi for the a) 3sinx=2cos(2x-1) b) sin(cosx)=3cos(x-2)      Log On


   



Question 639185: I need to solve the following for x where degrees 0 a) 3sinx=2cos(2x-1)
b) sin(cosx)=3cos(x-2)

Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
I need to solve the following for x where degrees 0 < x < 2pi for the
a) 3sinx=2cos(2x-1)
On your TI-84,  
Press MODE and make sure RADIAN is highlighted

Press Y=

Type so that you see:

\Y1=3sin(X)
\Y2=2cos(2X-1)

Press 2ND
Press TRACE
Press 7

You see this:



Press 2ND
Press TRACE
Press 5
Press ENTER
Press ENTER
Press the right arrow about 4 times to get the cursor near the first point
of intersection on the right of the x-axis
Press ENTER

Read at the bottom the screen

X = .67609059   Ignore the Y value

That's the first solution .67609059

Press 2ND
Press TRACE
Press 5
Press ENTER
Press ENTER
Press the right arrow about 15 times to get the cursor near the 2nd point
of intersection on the right of the x-axis.

Read at the bottom the screen

X = 2.9789026   Ignore the Y value

That's the second solution 2.9789026

---------------------------------

b) sin(cosx)=3cos(x-2)
The second problem is done the same way.

The graph looks like this:



The solutions are

.66718557 and 3.8087782

Edwin