SOLUTION: Solve: sin 3x*cos x + cos 3x*sin x=-1/2

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Question 639149: Solve:
sin 3x*cos x + cos 3x*sin x=-1/2

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
The easiest way to solove this is by recognizing that the left side of the equation fits the pattern for sin(A+B):
sin(A+B) = sin(A)cos(B) + cos(A)sin(B)
with the "A" being "3x" and the "B" being "x". So by sin((A+B) the left side is equal to:
sin(3x+x) = -1/2
or simply
sin(4x) = -1/2

This equation we can solve. We should recognize that 1/2 is a special angle value for sin and that the reference angle will be pi%2F6. Since the sin is negative, we know that the angle terminates in the 3rd or 4th quadrants. Putting the reference angle and the quadrants together we get:
4x+=+pi+%2B+pi%2F6+%2B+2pi%2An (for the 3rd quadrant)
which simplifies to
4x+=+7pi%2F6+%2B+2pi%2An (for the 3rd quadrant)
and
4x+=+-pi%2F6+%2B+2pi%2An (for the 4th quadrant)
(Instead of -pi%2F6 we could also have used 2pi+-+pi%2F6 or 11pi%2F6)

Now we just divide both sides by 4 (or multiply by 1/4):
x+=+7pi%2F24+%2B+pi%2An%2F2
and
x+=+-pi%2F24+%2B+pi%2An%2F2