SOLUTION: x^2+8x-22=0

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Question 639000: x^2+8x-22=0
Answer by jim_thompson5910(35256) (Show Source):
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For

a = 1

b = 8

c = -22

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x = \frac{-(8)\pm\sqrt{(8)^2-4(1)(-22)}}{2(1)}$

$x = \frac{-8\pm\sqrt{64-(-88)}}{2}$

$x = \frac{-8\pm\sqrt{152}}{2}$

$x = \frac{-8+\sqrt{152}}{2} \ \text{or} \ x = \frac{-8-\sqrt{152}}{2}$

$x = \frac{-8+2\sqrt{38}}{2} \ \text{or} \ x = \frac{-8-2\sqrt{38}}{2}$

$x \approx 2.16441 \ \text{or} \ x \approx -10.16441$

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Answer:

So the exact solutions are
$x = \frac{-8+2\sqrt{38}}{2} \ \text{or} \ x = \frac{-8-2\sqrt{38}}{2}$
and the approximate solutions are
$x \approx 2.16441 \ \text{or} \ x \approx -10.16441$