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x + 3 = y
3x + 4y = 7
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From the 1st equation we know that: y = (x+3)
Substitute (x+3) for y in the 2nd equation
3x + 4(x+3) = 7
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multiply what's inside the brackets
3x + 4x + 12 = 7
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Add the x's, subtract 12 from both sides
7x = 7 - 12
7x = -5
x =
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Find y
y = x + 3
substitute for x
y = + 3
Change 3 to 7ths
y = +
y =
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Solution: x = ; y =
:
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Check solution in the 2nd equation
3x + 4y = 7
Replace x and y
3() + 4() = 7 + = 7 = 7
7 = 7; confirms our solutions,
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