SOLUTION: 3X+4Y+12= 0 Y ???? ?? ?????? ????? ???

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Question 638955: 3X+4Y+12= 0 Y ???? ?? ?????? ????? ???
Answer by josh_jordan(263) About Me  (Show Source):
You can put this solution on YOUR website!
To solve for Y, we have to get Y by itself on one side of our equal sign. So, for 3x + 4y + 12 = 0, first we can subtract 12 from both sides of our equal sign:
3x + 4y + 12 - 12 = 0 - 12, giving us
3x + 4y = -12
Next, we can subtract 3x from both sides of our equal sign: 3x - 3x + 4y = -12 - 3x, giving us
4y = -12 - 3x
Finally, we can get the y by itself by dividing both sides by 4:
4y%2F4+=+%28-12+-+3x%29%2F4
This leaves us with
y+=+%28-12+-+3x%29%2F4
The right side of our equal sign can be simplified, because we know that
%28-12+-+3x%29%2F4 is the same thing as -%2812%2F4%29+-+3x%2F4
Reducing this down results in our final answer
Final Answer: y+=+-3+-+3x%2F4