SOLUTION: The number of inches in the perimeter of a square is 3 more than the number of square inches in its area. Find the legnth of a side. THANK YOU SO MUCH!

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Question 63877This question is from textbook Algebra 1
: The number of inches in the perimeter of a square is 3 more than the number of square inches in its area. Find the legnth of a side.
THANK YOU SO MUCH! This question is from textbook Algebra 1

Found 2 solutions by stanbon, ankor@dixie-net.com:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
The number of inches in the perimeter of a square is 3 more than the number of square inches in its area. Find the legnth of a side.
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Let a side of the square be "x".
The perimeter of the square is 4x.
The area of the square is x^2.
EQUATION:
4x-3=x^2
x^2-4x+3=0
(x-3)(x-1)=0
x=3
The length of a side is 3.
Cheers,
Stan H.

Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
Let s = one side of the square
:
We know: perimeter = 4s; area = s^2
:
The problem states the perimeter is 3" more than the area:
s^2 + 3 = 4s
:
s^2 - 4s + 3 = 0; our old friend, the quadratic equation
:
Factors easily to:
(s-3)(s-1) = 0
:
We have two solutions:
s = 3 and s = 1, both will satisfy the problem
:
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