SOLUTION: I really need some help. I really appreciate it. Simply the following expression, and rewrite it in equivalent form with positive exponents. -16x^-1y^-3 / 80x^-4y^-3. Thank you in

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I really need some help. I really appreciate it. Simply the following expression, and rewrite it in equivalent form with positive exponents. -16x^-1y^-3 / 80x^-4y^-3. Thank you in       Log On


   



Question 638560: I really need some help. I really appreciate it. Simply the following expression, and rewrite it in equivalent form with positive exponents. -16x^-1y^-3 / 80x^-4y^-3. Thank you in advance.
Found 3 solutions by MathTherapy, stanbon, fcabanski:
Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

I really need some help. I really appreciate it. Simply the following expression, and rewrite it in equivalent form with positive exponents. -16x^-1y^-3 / 80x^-4y^-3. Thank you in advance.

Considering that you didn't use parentheses, I suspect that the negative exponents "belong" to the variables, as follows:

%28%28-16x%5E-1%29%28y%5E-3%29%29%2F%28%2880x%5E-4%29%28y%5E-3%29%29 ---- ----- highlight_green%28-+x%5E3%2F5%29

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Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
-16x^-1y^-3 / 80x^-4y^-3. Thank you in advance.
----------
= [-16/xy^3] / [80/x^4y^3]
---------------
Invert the denominator and multiply to get:
= [-16/xy^3] * [x^4y^3/80]
-----
Cancel where you can to get:
= [-1/1] * [x^3/5]
------
= (-1/5)x^3
==============
Cheers,
Stan H.
===============

Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
When everything is multiplied you can add/subtract the exponents of like terms (all x's, all y's). Subtract the exponent in the denominator from the exponent in the numerator (divide like terms with exponents is the same as subtracting the exponent in the denominator):


x%5E%28-1-%28-4%29%29+=+x%5E3 and y%5E%28-3-%28-3%29%29+=+y%5E0+=+1. So this becomes:
%28-16+%2A+x%5E3+%2A+-1+%2A+1%29+%2F+80 = 16x%5E3+%2F+80 = x%5E3+%2F+5