Question 63855This question is from textbook An Incremental Development
: Divide 3x^3 - 5 by x - 1 and check
This question is from textbook An Incremental Development
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Divide 3x^3 - 5 by x - 1 and check
:
Using long division, Remember you have to have each degree of the equation represented,
hence the 0x^2 + 0x inserted in the divided expression:
(Using "...." to keep things lined up.)
:
.........................3x^2 + 3x + 3
..........--------------------
(x-1)| 3x^3 + 0x^2 + 0x - 5
............3x^3 - 3x^2
.............------------
........................+3x^2 + 0x
........................+3x^2 - 3x
........................------------
......................................+3x - 5
......................................+3x - 3
.......................................-------
................................................-2 remainder
:
The quotient: 3x^2 + 3x + 3, remainder -2/(x-1)
:
You check by mult: (x-1) * (3x^2 + 3x + 3)
you should get 3x^3 + 0 + 0 - 3, add the remaider of -2 and you will get the
original expression
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