SOLUTION: help! The general expression for consecutive multiples of 6 is 6n, 6(n+1), 6(n+2) etc. Find three consecutive multiples of 6 such that 4 times the first exceeds twice the third

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Question 63848This question is from textbook An Incremental Development
: help!
The general expression for consecutive multiples of 6 is 6n, 6(n+1), 6(n+2) etc. Find three consecutive multiples of 6 such that 4 times the first exceeds twice the third by 12.
This question is from textbook An Incremental Development

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
4*6N=2*6(N+2)+12
24N=12N+24+12
24N-12N=36
12N=36
N=36/12
N=3 SOLUTION
4*6*3=2*6(3+2)+12
72=12*5+12
72=60+12
72=72