Question 638378: The yearly production of a 5 foot orange tree is 42 pounds of oranges. A 15 foot tree produces 72 pounds. Let h represent the height of an orange tree and p the number of pounds of oranges produced.
List the ordered pairs (h,p)
1. What is the ordered pair for the first tree?
(5,42) ( did this part )
2. What is the second ordered pair?
(15,72)
3. Find the slope form of an equation of the line through the two ordered pairs.
a) p=3h+27
b) p-5=1/3(h-42)
c) p-42=3(h-5)
d) p-42=-3(h-5)
Use the equation above.
4. What is the predicted production of an 18 foot tree?
5. What is the predicted production of a 20 foot tree?
6. What is the predicted height in feet that produces 88 pounds of oranges?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The yearly production of a 5 foot orange tree is 42 pounds of oranges. A 15 foot tree produces 72 pounds. Let h represent the height of an orange tree and p the number of pounds of oranges produced.
List the ordered pairs (h,p)
1. What is the ordered pair for the first tree?
(5,42) ( did this part )
2. What is the second ordered pair?
(15,72)
3. Find the slope form of an equation of the line through the two ordered pairs
----
slope = (72-42)/(15-5) = 3
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Form: p = m*h+b
42 = 3*5+b
b = 27
Equation:
p = 3h+27
======================
a) p=3h+27
b) p-5=1/3(h-42)
c) p-42=3(h-5)
d) p-42=-3(h-5)
Use the equation above.
4. What is the predicted production of an 18 foot tree?
Solve: p = 3*18+27 = 81 lbs.
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5. What is the predicted production of a 20 foot tree?
Let h = 20 and solve for "p"
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6. What is the predicted height in feet that produces 88 pounds of oranges?
Solve for "h":
88 = 3h + 27
3h = 61
h = 20 1/3 feet
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cheers,
Stan H
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