Question 638248: hello..
please help me in this probability problem.
a circular dart board is divided into 4 sectors. 150^(0) of it is green, the second part is 90^(0) of the color red, 80^(0) is blue and 40^(0) is red. { please note that i have not make any errors in copying the question and i clearly specify that in my book the red color is mentioned two times}
calculate the probability that the dart hits :1.the green sector
:2.the blue sector
:3.a sector which is not blue.
:4.a red sector.
what i would like to know is that whether the total number of favourable outcomes is in degrees?? and how to calculate the 4th part of it.
thanking you in advance.!
post scrip-tum : by 150^(0) i meant 150 degrees. { i am not sure whether i have written it correctly. sorry for any inconvenience}
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! a circular dart board is divided into 4 sectors. 150^(0) of it is green, the second part is 90^(0) of the color red, 80^(0) is blue and 40^(0) is red. { please note that i have not make any errors in copying the question and i clearly specify that in my book the red color is mentioned two times}
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The total of the sectors = 360 degrees so I guess we can
assume there are 2 red sectors.
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calculate the probability that the dart hits
:1.the green sector:::P(green) = 150/360 = 5/12
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:2.the blue sector:::P(blue) = 80/360 = 2/9
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:3.not blue:: P(not blue) = 7/9
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:4.a red sector.:::P(red) = (90+40)/360 = 130/360 = 13/36
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Cheers,
Stan H.
what i would like to know is that whether the total number of favourable outcomes is in degrees?? and how to calculate the 4th part of it.
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