SOLUTION: Which expression is NOT equivalent to 1?
a) sin^2(theta)+cot^2(theta)sin^2(theta)
b) (sin^2(theta)/1-cos(theta))-cos(theta)
c) sec^2(theta)+tan^2(theta)
d) (cot^2(theta)sin^2(t
Algebra ->
Trigonometry-basics
-> SOLUTION: Which expression is NOT equivalent to 1?
a) sin^2(theta)+cot^2(theta)sin^2(theta)
b) (sin^2(theta)/1-cos(theta))-cos(theta)
c) sec^2(theta)+tan^2(theta)
d) (cot^2(theta)sin^2(t
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Question 637382: Which expression is NOT equivalent to 1?
a) sin^2(theta)+cot^2(theta)sin^2(theta)
b) (sin^2(theta)/1-cos(theta))-cos(theta)
c) sec^2(theta)+tan^2(theta)
d) (cot^2(theta)sin^2(theta))/cos^2(theta) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Which expression is NOT equivalent to 1?
a) sin^2(theta)+cot^2(theta)sin^2(theta)
b) (sin^2(theta)/1-cos(theta))-cos(theta)
c) sec^2(theta)+tan^2(theta)
d) (cot^2(theta)sin^2(theta))/cos^2(theta)
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Hint:
sin^2 + cos^2 = 1
Divide thru by cos^2
