Hi,
What is the value of the slope of the tangent to the curve at x = +2
f (x) = x ^ 3 - x ^ 2 - 2x | Taking the 1st Derivative
f '(x) =
f '(2) =
, the slope-value
y = mx + b
|Using (x,y) coordinate (2,0) to solve for b, 
0 = 12 + b
-12 = b
EQ of the tangent line at x = 2 is y = 6x-12
