SOLUTION: find the value of k so that the graph of kx+3y=4 is parallel to the line through (2,-k) and(4,-1). Please help

Algebra ->  Linear-equations -> SOLUTION: find the value of k so that the graph of kx+3y=4 is parallel to the line through (2,-k) and(4,-1). Please help       Log On


   

Question 637250: find the value of k so that the graph of kx+3y=4 is parallel to the line through (2,-k) and(4,-1). Please help
Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
kx + 3y = 4 can be expressed as y+=+%28-k%2F3%29x+%2B+4%2F3, therefore its slope is equal to -k%2F3.
The slope of the line joining the points (2, -k) and (4,-1) is equal to
%28-1-%28-k%29%29%2F%284-2%29+=+%28k-1%29%2F2.
Equate the two slopes because parallel line have equal slopes.
-k%2F3+=+%28k-1%29%2F2, multiply both sides by 6
-2k+=+3k-3
-5k+=+-3
highlight%28k+=+3%2F5%29