You can put this solution on YOUR website! 2x^2 + 13x + 20 / x^2 + x - 12 * x^2 + 2x - 15 / 2x^2 + 7x + 5
Factor where you can to get:
= [2x^2+8x+5x+20]/[(x+4)(x-3)]/[2x^2+5x+2x+5]
= [(2x+5)(x+4)/[(x+4)(x-3)]/[(x+1)(2x+5)]
Cancel where you can to get:
=(x+5)/(x+1)
Cheers,
Stan H.