SOLUTION: -5a^2-2ab+4b^2-2(2a^2-3b^2=
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Question 637186
:
-5a^2-2ab+4b^2-2(2a^2-3b^2=
Answer by
jim_thompson5910(35256)
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-5a^2-2ab+4b^2-2(2a^2-3b^2)
-5a^2-2ab+4b^2-4a^2+6b^2
-9a^2-2ab+10b^2
So the answer is -9a^2-2ab+10b^2