SOLUTION: Jonathan has $7.00 in nickels, dimes, and quarters. He has twice as many dimes as nickels, and 3 times as many quarters as nickels. He has 42 coins altogether. How many of each coi
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Question 63714: Jonathan has $7.00 in nickels, dimes, and quarters. He has twice as many dimes as nickels, and 3 times as many quarters as nickels. He has 42 coins altogether. How many of each coin does he have? Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! N+D+Q=42 GIVEN
700=5N+10D+25Q GIVEN
D=2N
Q=3N NOW WE SUBSTITUTE THESE BVALUES INTO EITHER EQUATION & WE GET
N+2N+3N=42
6N=42
N=42/6
N=7 NUMBER OF NICKELS
D=2*7
D=14 NUMBER OF DIMES
Q=3*7
Q=21 NUMBER OF QUARTERS
PROOF
700=5*7+10*14+25*21
700=35+140+525
700=700
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