Question 63713: 1. Find the slope of the line that passes through the points (-3, -5) and (3, 2).
2. Find the equation, in slope-intercept form, of the line that passes through the points (-3, 1) and (-2, -5).
3. Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x – 2y = 24 and passing through (1, 3).
4. Solve the system of equations using the substitution method.
If the answer is a unique solution, present it as an ordered pair: (x, y). If not, specify whether the answer is “no solution” or “infinitely many solutions.”
7x + y = 1
3x + 2y = -9
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website!
1. Find the slope of the line that passes through the points (-3, -5) and (3, 2).
slope= [2--5]/[3--3]=7/6
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2. Find the equation, in slope-intercept form, of the line that passes through the points (-3, 1) and (-2, -5).
slope = [-5-1]/[-2--3] = [-6]/[1]=-6
y-1=-6(x--3)
y=-6x-18+1
y=-6x-17
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3. Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x – 2y = 24 and passing through (1, 3).
The give line has slope=1/2; The line you want must have slope -2
y-3=-2(x-1)
y=-2x+5
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4. Solve the system of equations using the substitution method.
If the answer is a unique solution, present it as an ordered pair: (x, y). If not, specify whether the answer is “no solution” or “infinitely many solutions.”
1st: 7x + y = 1
2nd: 3x + 2y = -9
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Solve 1st for y: y=-7x+1
Substitute into 2nd to solve for x:
3x+2(-7x+1) = -9
3x-14x+2=-9
-11x=-11
x=1
y=-7(1)+1
y=-6
Solution: (1,-6)
Cheers,
Stan H.
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