SOLUTION: I believe this is a Quadratic Equation... I need to solve the equation graphically by finding x-intercepts. Confirm by using factoring to solve the equation. 4x^2-8x+3=0 Please

 

Hi,

4x^2-8x+3=0

(2x-1)(2x-3) = 0  x=intercepts are 1/2, 3/2

vertex form of a Parabola opening up(a>0) or down(a<0),  

where(h,k) is the vertex  and  x = h  is the Line of Symmetry

4x^2-8x+3= 4(x-1)^2 -4 + 3 = 4(x-1)^2 -1  

V(1,-1), parabola opens Upward, x= 1 the line of symmetry