SOLUTION: PLZPLZPLZZ......DEFINITELY NEED UR GUYZZ HELP ON THIS ONE.....UR HELP WILL BE THE MOST APPRECIATED THANK UU VERRY VERRY MUCH...OK HERES THE PROBLEMM: TAKE THE NUMBER 2, 7, 8 AND

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: PLZPLZPLZZ......DEFINITELY NEED UR GUYZZ HELP ON THIS ONE.....UR HELP WILL BE THE MOST APPRECIATED THANK UU VERRY VERRY MUCH...OK HERES THE PROBLEMM: TAKE THE NUMBER 2, 7, 8 AND      Log On


   

Question 63682: PLZPLZPLZZ......DEFINITELY NEED UR GUYZZ HELP ON THIS ONE.....UR HELP WILL BE THE MOST APPRECIATED THANK UU VERRY VERRY MUCH...OK HERES THE PROBLEMM:
TAKE THE NUMBER 2, 7, 8 AND 9--AND ONLY THOSE NUMBER AND USE ANY OPERATION AND OCMBINATIONS TO GET TO THE NUMBER 24.....BASICALLY U MAY DO ANY COMBO OF OPERATIONS TO GET TEH ANSWER 24......I CNT FIND THE ANSWER....HEEELLLLLPPP PLZ PLZ
Found 3 solutions by joyofmath, ankor@dixie-net.com, qdaman:
Answer by joyofmath(189) About Me  (Show Source):
You can put this solution on YOUR website!
%2827%2F9%29%2A8+=+24.
Also, %28%282%2B7%29%288%29%29%2Fsqrt%289%29+=+24.
Also, 2%287%2B8-sqrt%289%29%29+=+24.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
How about 2*(7+9)-8?

Answer by qdaman(1) About Me  (Show Source):
You can put this solution on YOUR website!
How About: 2(8+7-square root of 9=3)= 24
so 8+7=15 15-root9whichequals3=12 12x2=24