SOLUTION: Find the coordinates of the vertex for the parabola f(x)=-2x^2-2x

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Question 636757: Find the coordinates of the vertex for the parabola f(x)=-2x^2-2x
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Note: the vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk 

where(h,k) is the vertex  and  x = h  is the Line of Symmetry

f(x)= -2x^2-2x =+-2%28x%2B1%2F2%29%5E2+%2B+1%2F2     Note: 2%2F%282%2A2%29+=+1%2F2 & %28-2%29%28-1%2F4%29+=+1%2F2

V(-1/2,1/2),  Parabola opens Downward, line of symmetry is x = -.5