Question 636624: Assume that the average annual salary for a worker in the United States is $38,000 and that the annual salaries for Americans are normally distributed with a standard deviation equal to $7,000. Find the following:
(A) What percentage of Americans earn below $25,000?
(B) What percentage of Americans earn above $46,000?
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website!
Hi,
mean = $38,000 and SD = $7000
(A) What percentage of Americans earn below $25,000? P(z < -1) = (100-68.27)/2 = 15.87%
(B) What percentage of Americans earn above $46,000? P(z > 1) = 15.87%
For the normal distribution:
one standard deviation from the mean accounts for about 68.27% of the set
two standard deviations from the mean account for about 95.4%
and three standard deviations from the mean account for about 99.7%.
Important to Understand z -values as they relate to the Standard Normal curve:
Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted.
Note: z = 0 (x value the mean) 50% of the area under the curve is to the left and 50% to the right

|
|
|