Question 636451: Solve for x.
6^(log_6 of x^2) = x+30
2-log_(2-x)of 2x = 0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Solve for x.
..
6^(log_6 of x^2) = x+30
base raised to log of number=number
x^2=x+30
x^2-x-30=0
(x-6)(x+5)=0
x=-5
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2-log_(2-x)of 2x = 0
log_(2-x)of 2x =2
reads: log base(2-x) of 2x=2
(2-x)^2=2x (base raised to log of number=number
4-4x+x^2=2x
x^2-6x+4=0
solve by quadratic formula:
x≈5.236 (reject, (2-x)>0)
or
x=0.764
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