SOLUTION: solve by factoring show check each answer here is the problem 2x^2+3x=2 heres how I solved the problem 2x^2+3x-2=0

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Question 636433: solve by factoring show check each answer
here is the problem 2x^2+3x=2
heres how I solved the problem
2x^2+3x-2=0
2x^2=4x-x-2=0
2x(x+2)-(x+2)=0
(x+2)(2x-1)=0
x=2 please show me how to check each answer
Answer by MathTherapy(10552) About Me  (Show Source):
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solve by factoring show check each answer
here is the problem 2x^2+3x=2
heres how I solved the problem
2x^2+3x-2=0
2x^2=4x-x-2=0
2x(x+2)-(x+2)=0
(x+2)(2x-1)=0
x=2 please show me how to check each answer

First, your solution, x+=+2 is incorrect. Since x + 2 = 0, then x+=+-+2
Second, there’s another solution, as x+=+1%2F2
Since x = - 2, we will substitute - 2 for x into the original equation to determine if this value for x makes the equation true

x = - 2
2x%5E2+%2B+3x+=+2 becomes:
2%28-+2%29%5E2+%2B+3%28-+2%29+=+2
2(4) - 6 = 2
8+-+6+=+2. This is true.

The same concept applies to the check for the 2nd solution: x+=+1%2F2

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