SOLUTION: 7. A sample of 320 mobile phone batteries contained 16 defective batteries. How many defective batteries would you expect to find in a sample of 3000? thanks so much and have

Algebra ->  Rational-functions -> SOLUTION: 7. A sample of 320 mobile phone batteries contained 16 defective batteries. How many defective batteries would you expect to find in a sample of 3000? thanks so much and have      Log On


   



Question 636339: 7. A sample of 320 mobile phone batteries contained 16 defective batteries. How many defective batteries would you expect to find in a sample of 3000?

thanks so much and have a terrific weekend!

Answer by math-vortex(648) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, there--

The problem:
A sample of 320 mobile phone batteries contained 16 defective batteries. How many defective
batteries would you expect to find in a sample of 3000?

A solution:
You can use proportional reasoning to solve this problem. Let x be the number of defective
batteries in the larger sample.

 THere are several different ways to set up a proportion for this problem. Just remember to 
match your units. I like to say the proportion out loud. This keeps me from getting the 
proportion upside down. Here is one possible proportion:

[number of DEFECTIVES in SMALLER sample] over [number of BATTERIES in SMALLER sample] 
equals [number of DEFECTIVES in LARGER sample] over [number of BATTERIES in LARGER 
sample]

Now we substitute in the known values and variable.
16%2F320=x%2F3000

Solve for x.
We can cross-multiply here. (NOTE: many teachers frown on the cross-multiply technique. 
If your teacher is one of those, see an alternate method below.)

%2816%29%283000%29=320x

x=%28%2816%29%283000%29%29%2F320

x=150

We would expect to find 150 defective batteries in the larger sample.

SOLUTION METHOD WITHOUT CROSS_MULTIPLYING
16%2F320=x%2F3000

Multiply both sides of the equation by 3000 to isolate the variable on the right side.

3000%2A%2816%2F320%29=3000%2A%28x%2F3000%29

%28%283000%2A16%29%2F320%29=x

Simplify left side using multiplication and division.
x=150

We have the same answer, 150 defective batteries in the larger sample.

Feel free to email if you have questions about this.

Ms.Figge
math.in.the.vortex@gmail.com