Question 636301: Hi, I have quite a bit of troublesome problem here...
What is the log_4 of sq.rt2?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Hi, I have quite a bit of troublesome problem here...
What is the log_4 of sq.rt2?
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log4(sqrt(2) = log(sqrt(2))/log(4)
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Let the base be "2".
Then log2(sqrt(2))/log2(4)
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= (1/2)/2
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= 1/4
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Cheers,
Stan H.
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